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# Math Competition Problems - Problem of the Week - 20

Updated: Jun 17, 2021

Andrew is doing some tidying. He can tidy 2 big rooms in the same time it takes to tidy 3 small rooms. He can tidy one big room and three small rooms in 90 minutes. How long will it take him to tidy 3 big rooms and 6 small rooms? - AMC (Australian Mathematical Competition) Upper Primary 2018, Question 20 Let a big circle represent the time taken to tidy a big room.

Let a small circle represent the time taken to tidy a small room

Since he can tidy 2 big rooms at the same time as 3 small rooms,

2 big circles = 3 small circles He can tidy 1 big room and 3 small rooms in 90 mins.

So, 1 big circle + 3 small circles = 90 mins We can replace the 3 small circles with 2 big circles because they are equivalent.

Hence our equation becomes 3 big circles = 90 mins Hence one big circle has to be 30 mins. Which means he takes 30 mins to clean the big room Since, We can replace the big circle with 30 and get

30 + 3 small circles = 90 So we know the 3 small circles have to be 60. Which means 1 small circle = 20. So he takes 20 minutes to tidy a small room. So Andrew takes 30 minutes to tidy 1 Big Room

and 20 minutes to tidy 1 Small Room.

We know it is right because time taken for 2 big rooms is 30*2=60 and time taken for 3 small rooms is 20*3=60 and they are equal.

Which means for 3 big rooms it will take him 90 minutes and 6 small rooms it will take him 120 minutes, giving a total of 210 minutes or 3 hours and 30 minutes.

Want to prepare for AMC? Working out the problems by yourself is the only way to prepare for it.

### Try out a similar problem.

5 Oranges cost the same as 4 Apples. If 4 Apples and 4 Oranges cost \$5.40, then how much does 5 Oranges and 3 Apples cost? Interesting Math Problem 113

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